duck-booking-tool/api/views.py
Gergely Polonkai 8fadaba002 Move api.viewsets to api.views
Naming is much more clear this way
2015-10-19 17:09:16 +02:00

57 lines
2.0 KiB
Python

# -*- coding: utf-8 -*-
from django.conf import settings
from django.contrib.auth.models import User
from django.shortcuts import get_object_or_404
from rest_framework import viewsets
from rest_framework.decorators import detail_route, list_route
from rest_framework.permissions import IsAuthenticated
from rest_framework.response import Response
from .serializers import DuckSerializer, CompetenceSerializer
from booking.models import Duck, Competence, Booking
class DuckViewSet(viewsets.ModelViewSet):
serializer_class = DuckSerializer
queryset = Duck.objects.all()
@detail_route(methods=['post'], permission_classes=[IsAuthenticated])
def book(self, request, pk=None):
duck = self.get_object()
competence = get_object_or_404(Competence, pk=request.data['competence'])
force = request.data.get('force', False)
# If the duck is already booked, return 'already-booked' as the
# result
if duck.booked_by() != None:
return Response({'status': 'already-booked'})
# Result 'fail' means a problem
result = 'fail'
comp_level = 0
# Check if the duck has the requested competence
dcomp_list = duck.duckcompetence_set.filter(comp=competence)
if len(dcomp_list) < 1:
comp_level = 0
else:
comp_level = dcomp_list[0].level()
# If the competence level is too low, set result to 'bad-comp'
if comp_level <= settings.COMP_WARN_LEVEL:
result = 'bad-comp'
# If the duck has high enough competence or the booking is
# forced, return status 'success'
if result != 'bad-comp' or force:
result = 'ok'
booking = Booking(duck=duck, user=request.user, comp_req=competence)
booking.save()
return Response({'status': result})
@list_route(methods=['post'], permission_classes=[IsAuthenticated])
def donate(self, request):
return Response({'Woot!'})